HSSC Group D CET Answer Key 2023, Paper Solution PDF Download

Haryana Staff Selection Commission will release the answer key for Common Eligibility Test Group D posts most probably in the last week of October 2023 at https://hssc.gov.in/. There are a total number of 13,536 vacancies, against which a huge number of aspirants across the State, and now all these are eagerly waiting for the release of a paper solution to download it and compare with candidate’s response and evaluate the tentative score.

HSSC Group D CET Answer Key 2023

Candidates who want to be appointed on various Group D posts across the various organisations and departments of Haryana took part in the Common Eligibility Test held on 21 and 22 October 2023 in offline and now all the candidates are eagerly waiting for release of the answer key, which may be available at https://hssc.gov.in/ most probably within 10 days after the examination, once the answer key is made public officially the direct link to download it from all sets will be activated inside the table available below.

Exam Name  Common Eligibility Test 2023
Organizer  Haryana Staff Selection Commission 
Post Name Group D
Vacancies 13,536
Exam Date  21 & 22 October 2023
Answer Key  October 2023
Official Website  https://hssc.gov.in/

The answer key for the Haryana Staff Selection Commission’s Group D exam, which took place on October 21 and 22, 2023, will serve as a comprehensive guide for aspirants. This key is anticipated to contain the correct responses to the 100 multiple-choice questions presented during the examination. By downloading it candidates can assess their performance, determine their strengths and weaknesses, and calculate their tentative scores and make sense that he or she is likely to pass the examination and call for a second stage of the selection process.

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HSSC Group D Answer Key 2023

Date for releasing the answer key for Group D posts has not yet confirmed officially by the Haryana Staff Service Commission, it you are among those lakhs of aspirants who took part in the first stage of the selection process then you must know that the answer key as gazette will be available at https://hssc.gov.in/. The paper solution for HSSC Group D CET 2023 will carry correct responses for all MCQs asked in the examination held on 21 and 22 October 2023. Step-by-step instructions to download the answer key are also available below, scroll down to know the procedure.

HSSC Group D CET Answer Key 2023

How to download the HSSC Group D Answer Key 2023?

To download the answer key for the Haryana Staff Selection Commission’s GROUP-D written examination on October 21st and 22nd, 2023, follow these steps:

  1. Visit the official website of the Haryana Staff Selection Commission at https://hssc.gov.in/.
  2. Look for the section related to “Download Answer Key for GROUP-D written examination (21.10.2023 and 22.10.2023)” on the website.
  3. You will likely see options for Sets A, B, C, and D, tap on the respective set (A, B, C, or D) that you want to download.

HSSC CET Group D Answer Key Raise Objection 2023

If you find discrepancies or have concerns with the answer key provided by the Haryana Staff Selection Commission for the Common Eligibility Test 2023 Group D posts, one will be able to raise objection against using the direct link, which will be activated on the official website of the HSSC, which is accessible at  https://hssc.gov.in/. To challenge the answer key for HSSC Group D CET 2023, an individual will have to pay the required amount and provide valid proof with a proper description of error on the answer key.

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How to evaluate the tentative score using HSSC Group D Answer Key 2023?

To evaluate the tentative score for HSSC Group D Common Eligibility Test 2023, you have to go through the step-by-step instructions available below.

  • Download the answer key for the HSSC Group D CET 2023 from the official website of the Haryana Staff Selection Commission.
  • Compare the paper solution with your response and find out the number of correct responses.
  • At the end, you have to multiply the number of correct responses with 0.95 to evaluate the tentative score.

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